If it's not what You are looking for type in the equation solver your own equation and let us solve it.
10y^2+12y+2=0
a = 10; b = 12; c = +2;
Δ = b2-4ac
Δ = 122-4·10·2
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-8}{2*10}=\frac{-20}{20} =-1 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+8}{2*10}=\frac{-4}{20} =-1/5 $
| C-(9-3c)=-13 | | 7x-6(4x+21)=-24 | | 11r=11r | | 160+24x=180+20x | | 203=2w+23 | | 14-x+10x=68 | | -20=-8v+5(v+2) | | 1x+2(x-5)=2x+2 | | 40=4x+4+4x | | 1/5x+2=-1 | | -8b^2-18b-9=0 | | -4x+8=2×+10 | | 44=8x+3+4x | | 4)24=2(2x+6) | | m-2=35 | | 44=8x+4+4x | | -4+8=2x+10 | | 4(1x-3)+7=5(1x-1)-1x | | 3)6(-2+3x)=6 | | 44=8x+4+3x | | -70x+2600=-135x+4550 | | 2a^2+5a=12 | | 64=8(r=4) | | (7m-13)=(5m+3) | | X+4-7x=11,5-2,5x-14,5 | | -5/15=(-10/9)*u | | x3–22x=9x2 | | -2(1x-1)=8 | | -70x+2600=1690 | | -4m^2-20m+24=0 | | (x-9)-(x+4)=6x | | 2x+122=584 |